For the PNP transistor in this circuit beta 120 and VEB For

For the PNP transistor in this circuit, beta = 120 and V_EB For the NPN transistor, V_EB = 0.65v. and V_BE = 0.75v. Find VH to five decimal places.

Ib1= base current in npn transistor

=(30-VBE)/10

=2.925 mA

Ic1= collector current in npn=120*ib1=351 mA

Ib2= base current in PNP= (30-VEB)/10=2.935 mA

Ic2= collector current in PNP =120*ib2=352.2 mA

Apply KCL at node VN.

(30-VN)-Ic1=VN-Ic2

VN= 15+(Ic2-Ic1)/2= 15+0.6= 15.6 v