y1 and y112x interval x01 find the area of the solid formed
y=1 and y=1-1/2x interval x=[0,1] find the area of the solid formed when the inside of these two functions is rotated about the y-axis
Solution
y=1-x/2
 implies
 x/2=1-y
 x=2-2y
 when x=0, y=1
 x=1, y=1/2
The volume is
1/21(1-(2-2y)^2) dy=/3
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