Solve the following problem written in the style of a questi

Solve the following problem, written in the style of a question from the Arithmetic in Nine Sections (see problem study 7.1) Round your answer to the nearest integer Given a field of width 1,1/2,1/3,1/4,1/5, and 1/6 pu with an area of 1 mu what is the length of the field?

Solution

Given field of width 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 pu

Area of 1 mu, what is the length of the field ?

Area of field = length x width

1 mu = 240 square pu.

width = 1 + 0.5 + 0.33 + 0.25 + 0.2 + 0.16 = 2.44 pu

length = 240 / 2.44 = 98.36 pu

7.1) a) Given width = 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10 + 1/11 + 1/12

= 1 + 0.5 + 0.33 + 0.25 + 0.2 + 0.16 + 0.14 + 0.125 + 0.11 + 0.1 + 0.09 + 0.08

= 3.085 pu

Area = 1 mu = 240 square pu

Length of the field = Area / Width

= 240 / 3.085

= 77.79 pu

b) Given square field of area 71,824 square pu, side of the sqaure = sqrt(Area)

= sqrt(71824)

= 268 pu

c) Given field in the form of segment of circle, base = 78.5 pu, sagitta = 13.77 pu, Area = ?

Area of the field = s (b + s)/2

= 13.77 * (78.5 + 13.77)/2

= 635.37 square pu

d) Question is incomplete. Cannot be answered.