i have a problem in second question and part b and c if you
 i have a problem in second question and part (b) and (c) if you help me it would be greate..
Solution
The information given is tabulated as follows for easy reference.
Sample size = 170000
Women having cancer = 4500
Sample proportion = 0.0265
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Received two independents test positive
Chance for having cancer = P(both tests give correct result)
=0.95(0.95)
= 0.9025
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If 3 positive results are got prob for having real cancer
= P(3 positive results and having real cancer)/P(having real cancer)
=(0.95)3= 0.857375
| Positve | Negative | |
| woman has cancer | 95% | 5% | 
| woman does not have cancer | 1% | 99% | 

