Please fill in the blanks in the equation Subtract 2x 2x2

Please fill in the blanks in the equation

Subtract. 2/x - 2x/2 - 7x +2 The denominator of 2 is_____, so the LCM of the entire expression is x(2 2 -7 7x). Change each rational expression to an equivalent expression that has the LCM for the denominator. 2/x.__-__x/2-7x =__-__x/x(__-__x) 2x/2-7x. x/x =__x^2/x(2-7x) 2/1. X(__-__x)/x(2-7x) = 2x(__-__x)/x(__-__x) =__x -__x/x(__-__x)

Solution

(2/X) - (2X/(2-7X)) + 2

LCM = X(2-7X)

2(2-7X) - 2X*X + 2X(2-7X)

X(2-7X)

= 4 - 14X - 2X² + 4X - 14X²

  X(2-7X)

= (-16X² - 10X +4)/(X(2-7X))

Part 2 of 4

Asuming unknowns as a and b

(i) (2/X). ((a-bX)/(2-7X)) = (2a - 2bX) / X(2 - 7X)

(II) (2X/(2-7X)).(X/X) = 2X²/X(2-7X)

(III) (2/1).(X(a-bX)/X(2-7X)) = (2X(a - b)X) / (X(2-7X)) = (2aX - 2bX²) / X(2 - 7X)