06 nausa 04 dizziness will suffer nausia but not dizziness i

.06 nausa

.04 dizziness

will suffer nausia but not dizziness is .03

what is the chances they will have neither.

Solution

Given P(nausa) =0.06

P(dizziness) = 0.04

P(suffer nausia but not dizziness) =0.03

--> P(nausia)- P(nausia and dizziness) =0.03

--> 0.06 - P(nausia and dizziness) = 0.03

So P(nausia and dizziness)= 0.06-0.03 =0.03

So the chances they will have neither is

P(neither) = 1-P(nausia or dizziness)

=1-P(nausia) - P(dizzines) + P(nausia and dizziness)

=1-0.06-0.04+0.03

=0.93