Calculate the probabilities and expected values for the foll
Solution
a)
Note that the probability of x successes out of n trials is          
           
 P(x) = C(N-K, n-x) C(K, x) / C(N, n)          
           
 where          
 N = population size =    28      
 K = number of successes in the population =    14      
 n = sample size =    12      
 x = number of successes in the sample = 12/2 =    6      
           
 Thus,          
           
 P(   6   ) =    0.296432898 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]
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b)
Note that the probability of x successes out of n trials is          
           
 P(x) = C(N-K, n-x) C(K, x) / C(N, n)          
           
 where          
 N = population size =    28      
 K = number of successes in the population =    14      
 n = sample size =    12      
 x = number of successes in the sample =    0      
           
 Thus,          
           
 P(   0   ) =    2.99128*10^-6 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]
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c)
Note that the probability of x successes out of n trials is          
           
 P(x) = C(N-K, n-x) C(K, x) / C(N, n)          
           
 where          
 N = population size =    28      
 K = number of successes in the population =    14      
 n = sample size =    12      
 x = number of successes in the sample =    5      
           
 Thus,          
           
 P(   5   ) =    0.225853637 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]


