Calculate the probabilities and expected values for the foll
Solution
a)
Note that the probability of x successes out of n trials is
P(x) = C(N-K, n-x) C(K, x) / C(N, n)
where
N = population size = 28
K = number of successes in the population = 14
n = sample size = 12
x = number of successes in the sample = 12/2 = 6
Thus,
P( 6 ) = 0.296432898 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]
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b)
Note that the probability of x successes out of n trials is
P(x) = C(N-K, n-x) C(K, x) / C(N, n)
where
N = population size = 28
K = number of successes in the population = 14
n = sample size = 12
x = number of successes in the sample = 0
Thus,
P( 0 ) = 2.99128*10^-6 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]
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c)
Note that the probability of x successes out of n trials is
P(x) = C(N-K, n-x) C(K, x) / C(N, n)
where
N = population size = 28
K = number of successes in the population = 14
n = sample size = 12
x = number of successes in the sample = 5
Thus,
P( 5 ) = 0.225853637 [ANSWER]
Here,
E(x) = N n / K = 6 [ANSWER]

