A servomotor is connected to a forearm axis drive shaft with

A servomotor is connected to a forearm axis drive shaft without any reduction drive components. The maximum weight of the part and gripper at the end of the forearm is 75 pounds and the forearm length is 90 centimeters. Determine the motor torque in foot-pounds required to prevent the forearm from rotating under the gripper and part weight. (Enter your answer as a number without the units.) Who can please help with this?

Solution

torque=multiple of force or weight with length =F*L

90 centimeter = 2.95 foot

therefore, in foot and pound terms ,

Torque = 75*2.95

=221.25 lb.ft