There was carried out an investigation to study the toxic ef

There was carried out an investigation to study the toxic effects of mercury. Ten different concentrations of mercury (0, 1, 5, 10, 50, 100, 200, 300, 400, and 500 mg/L) were compared with respect to their effects on average dry weight (per 100 seven-day-old seedlings). The basic experiment was replicated four times for a total of 50 dryweight observations (five for each treatment level). The article reported an ANOVA F statistic value of 1.895.

Using a significance level of .05, test the null hypothesis that the true mean dry weight is the same for all 10 concentration levels.
---Select--- 0 0.001 0.01 0.05 0.1 < P <  ---Select--- 0.001 0.01 0.05 0.1 1

Solution

Solution:

The null hypothesis and are Alternative:

Ho: all the proportions of the population are equal
H1: Not all of the population proportions are equal

Calculating the degrees of freedom of the numerator is:
k-1 = 4-1 = 3

Calculating the denominator degrees of freedom we have:
k (n-1) = 4 (10-1) = 36

with 3 degrees of freedom in the numerator, 36 degrees of freedom in the denominator and a significance level of 0.05 with table reading is obtained distribution F

F = 2.8805

Decision:

as F (test) is less than F (table) (1.895 <2.8805), Ho passes, so there are no real differences in sample weights, ie, all ratios are equal.

Regards!