Given a random sample of twelve measurements recorded a samp

Given a random sample of twelve measurements recorded a sample mean 52 with a standard deviation 6. Using 90% confidence, what is the maximal margin of error for this problem? Find an interval estimate for the true mean. Interpret the result.

Solution

Solution

Margin of error = Critial value * standard error

= 1.79588 * 6/sqrt (12) = 3.11

Lower confidence limit = 52 - 3.11 = 48.89

Upper confidence limit = 52 + 3.11 = 55.11

So,the required confidence limit = (48.89, 55.11)