2x48 if you divide by 2 first then add 4 to both sides then

2x-4=8

if you divide by 2 first, then add 4 to both sides then x = 8

when you plug in 8 to the equation 2(8)-4 that does not equal 8

although when you add 4 to both sides then you divide by 2 you get 6

2(6)-4= that does infact equal 8

why is this? why do we have to add before we divide to find x

Solution:

Look into first two lines \"

2x-4=8

if you divide by 2 first, then add 4 to both sides then x = 8 \"

Here we are dividing only one side ( First ) and this is an incorrect approch

As we know that when we perform any operation on an equation then it must be done on both side of equal (= ) sign.

2x - 4 = 8 ( If we divide by 2 first then we get x-2= 8 and this is an incorrect approch )

due to this above incorrect approch we are getting conflict in value of x

( x = 8 in first care and x= 6 in second case)

We can solve either by division or addtion operations but make sure that operation must be perform on the both side of the equation.

Situation1: Addition first and then division

2x - 4 = 8 ( On adding 4 both side )

2x = 12 ( on dividing by 2 on both side )

x =6

Sitution2: Division and addtion

(2x -4 ) = 8 ( On dividing equation by 2 on both sides)

x - 2 = 4 ( adding 2 on both side )

x = 6

In both case answers are same

Hence proved