Murder Rate The data represent the murder rate per 10000 ind
Murder Rate: The data represent the murder rate per 100,00 individuals in a sample of selected cities in the United States. Find the variance and standard deviation. Class limits 5-11 12-18 19-25 26-32 33-39-40-46 Frequency 8 5 7 1 1 3. Please included the steps and I\'m just a little confused. Thank you
Solution
First prepare a frequency distribution table as follows:
For finding std deviation we find mid point of each class interval and take it as x.
Frequency is marked as f
Mean = sum of all xf/sum of all f = 487/25
=19.48
E(X^2) = sum of x^2f/25
=508.36
Hence var(x) =508.36-19.48^2
= 128.8896
Std dev = 11.3593
| Class limits | Midpt x | Frequency | x*f | x^2f |
| 5-11 | 8 | 8 | 64 | 512 |
| 12-18 | 15 | 5 | 75 | 1125 |
| 19-25 | 22 | 7 | 154 | 3388 |
| 26-32 | 29 | 1 | 29 | 841 |
| 33-39 | 36 | 1 | 36 | 1296 |
| 40-46 | 43 | 3 | 129 | 5547 |
| Total | 25 | 487 | 12709 |
