To determine the characteristics of a coil of wire a student
Solution
When Coil is connected to a DC battery ,Resistance of the coil is given by
R=V/I =12/0.752
R=15.96 ohms
When the coil is connected to AC supply ,the Impedance of the coil is given by
Z=Vrms/Irms =22.2/0.475
Z=46.74 ohms
SInce
Z=sqrt[R2+XL2]
So inductive reactance is
XL=sqrt[46.742-15.962] =43.93 ohms
since XL=2pifL
=>L=XL/2pif =43.93/2pi*121
L=0.05778 H or 57.78 mH
