A car is parked on a cliff overlooking the ocean on an incli

A car is parked on a cliff overlooking the ocean
on an incline that makes an angle of 18.0?
below the horizontal. The negligent driver
leaves the car in neutral, and the emergency
brakes are defective. The car rolls from rest
down the incline with a constant acceleration
of 2.00 m/s2 and travels 43.0 m to the edge of
the cliff. The cliff is 40.0 m above the ocean.
The acceleration of gravity is 9.81 m/s2 .
a) How long is the car in the air? Answer
in units of s.
b) What is the car

Solution

s = (at^2)/2
43 = (2*t^2)/2
t = sqrt(43) seconds to go the 43 meters
v = at = 2sqrt(43) m/sec when the car leaves the incline and is airborne.
v =~ 13.114877 m/sec
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The vertical component of v is v*sin(18) = -4.05272 m/sec (neg since is down)
The horizontal part of v is v*cos(18) = 12.473 m/sec
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h(t) = -9.81t^2 - 4.05272t + 40
h(0) = 40 (when it leaves the ground)
Find t at h = 0 (when it hits the water)
-9.81t^2 - 4.05272t + 40 = 0