If tidal volume is 500 mL anatomic dead space is 125 mL and

If tidal volume is 500 mL, anatomic dead space is 125 mL, and respiration rate is 14 breaths per minute, alveolar ventilation would be _______ L/min.

Solution

As we know

alveolar minute ventilation = (respiratory rate) x (tidal volume – dead air space)

respiratory rate= 14 breaths/min

tidal volume=500

dead air space=125

alveolar minute ventilation= 14X(500-125)=14X375=5250 ml/min=5.25L/min