Homework SourseThe Quality Control Department employs five technicians duri
The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technician instructed the production foreman to shut down the manufacturing process last week.
Compute the mean of the sample means and compare it to the population mean. (Round your answers to 1 decimal place.)
| The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technician instructed the production foreman to shut down the manufacturing process last week. |
Solution
(a) 2 technicians can be selected from 5 technicians in C(5, 2) ways = 10 ways. \\ 10 different samples of 2 technicians each are possible.
(b) Let the 5 technicians be a, b, c, d, e in that order.
Sample
ab
ac
ad
ae
bc
bd
be
cd
ce
de
Mean number of shutdowns ordered
= (n1 + n2)/2
3.5
4.5
5
3.5
4
4.5
3
5.5
4
4.5
(c) Mean of the sample means = Sum of the sample means/Number of samples
= 42/10 = 4.2 shutdowns.
Population mean = (4 + 3 + 5 + 6 + 3)/5 = 21/5 = 4.2 shutdowns
Mean of the sample means = Population mean.
| (a) 2 technicians can be selected from 5 technicians in C(5, 2) ways = 10 ways. \\ 10 different samples of 2 technicians each are possible. | ||||||||||||||||||||||
| (b) Let the 5 technicians be a, b, c, d, e in that order.
| ||||||||||||||||||||||
| (c) Mean of the sample means = Sum of the sample means/Number of samples = 42/10 = 4.2 shutdowns. Population mean = (4 + 3 + 5 + 6 + 3)/5 = 21/5 = 4.2 shutdowns Mean of the sample means = Population mean. |
