find the exact value under the given conditions sin817 pi2

find the exact value under the given conditions.

sin()=8/17, pi/2< ; cos=20/29, 0<<pi/2 Find sin(-)

Solution

sin(alpha)=8/17                                                pi/2< alpha<pi

here opposite=8   hypotenuse=17

adjacent=sqrt(hypotenuse2-opposite2) =   sqrt(172-82)=15

In second quadrant cosine is negative

Therefore cos alpha=-15/17

            cos beta= 20/29

adjacent=20       hypotenuse=29

opposite = sqrt(hypotenuse2-adjacent2) = sqrt(292-202)= 21

sin beta=21/29

sin(alpha-beta) =   sin alpha cos beta   - cos alpha sin beta = (8/17)(20/29)-(-15/17)(21/29)

                                                                                                      = (160/493)+ (315/493)= 475/493

find the exact value under the given conditions. sin()=8/17, pi/2< ; cos=20/29, 0<<pi/2 Find sin(-)Solution sin(alpha)=8/17 pi/2< alpha<pi here o

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