Let PZ 042 PY 039 and PZ Y 018 Use a Venn diagram to find
Let P(Z) = 0.42, P(Y) = 0.39, and P(Z Y) = 0.18. Use a Venn diagram to find P(Z\' Y\'), (Z\' Y\'), P(Z\' Y\'), and P(Z Y\').
Solution
a)
Using a Venn Diagram, we see that
P(Z\' Y\') = 1 - [P(Z) + P(Y) - P(ZY)]
= 1 - (0.42+0.39-0.18)
= 0.37 [ANSWER]
b)
P(Z Y\') = P(Z) - P(ZY) = 0.42 - 0.18 = 0.24 [ANSWER]
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Hi! You problem says find: P(Z\' Y\'), (Z\' Y\'), P(Z\' Y\'), and P(Z Y\').
However, there are 3 P(Z\' Y\') here (the first 3 are identical). Please resubmit this question if this is an error. That way we can continue helping you! Thanks!
