Homework SourseRun a between group ANOVA using the following data measuring
Run a between group ANOVA using the following data measuring student alcohol by University and report the results.
SCSU
YALE
UNH
4
7
5
6
5
4
4
3
7
3
6
6
5
8
6
| SCSU | YALE | UNH |
| 4 | 7 | 5 |
| 6 | 5 | 4 |
| 4 | 3 | 7 |
| 3 | 6 | 6 |
| 5 | 8 | 6 |
Solution
Using technology to run anova, we get these results:
Thus, as we see, we have a big P value,
P = 0.2923.
Thus, even at 0.10 level only, we cannot reject the null hypothesis that the means of the three groups are the same.
Thus, there is is no significant evidence that at least 2 of these means are not equal (at almost any usual significance level). [CONCLUSION]
| Anova: Single Factor | ||||||
| SUMMARY | ||||||
| Groups | Count | Sum | Average | Variance | ||
| Column 1 | 5 | 22 | 4.4 | 1.3 | ||
| Column 2 | 5 | 29 | 5.8 | 3.7 | ||
| Column 3 | 5 | 28 | 5.6 | 1.3 | ||
| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | P-value | F crit |
| Between Groups | 5.733333 | 2 | 2.866667 | 1.365079 | 0.292309 | 3.885294 |
| Within Groups | 25.2 | 12 | 2.1 | |||
| Total | 30.93333 | 14 |
