Im given the answers just cant get to the correct answers Q5
I\'m given the answers, just can\'t get to the correct answers.
 Q5 answers: 8.4353*10^(-4) slug/ft^3 and 31,471 ft
 Problem 5. 12 points] An altimeter set for sea-level standard pressure indicates an altitude of 30,000 ft. If the outside ambient temperature is 25°F, find the air density and the density altitude. Problem 6. [2 points] Consider an airplane flying at some real, geometric altitude. The outside (ambient) pressure and temperature are 0.65x105 N/m2 and 225 K, respectively. Calculate the pressure and density altitudes at which this airplane is flying. Solution
Station Pressure = Sea-level Barometric Pressure - (Physical Altitude / 1000)
Station Pressure = 30.14 - (30000/1000) = 0.14 inches of Hg
Staton Pressure = 474.0944 Pa
PV=MRT/Z
M/V =PZ/RT [ Z of Air = 14 ]
density = P/RT = 474.094*14/ (8.31*241.483) = 3.314 Kg/m3
density = 6.43 * 104 slug/ft3
ISA Temperature = 59 - (Pressure Altitude / 1000) * 3.6
ISA temperature = 59 - ( 30000/1000)*3.6
ISA Temperature = -49
Correction (feet) = (Actual Temperature - ISA Temperature) * 66.67
Correction = (-25 - (-49)) *66.67
correction = 1600.8
Density Altitude = Pressure Altitude + Temperature Correction.
Density Altitude = 30000+1600.08
Density Altitude =31600.08
![I\'m given the answers, just can\'t get to the correct answers. Q5 answers: 8.4353*10^(-4) slug/ft^3 and 31,471 ft Problem 5. 12 points] An altimeter set for se I\'m given the answers, just can\'t get to the correct answers. Q5 answers: 8.4353*10^(-4) slug/ft^3 and 31,471 ft Problem 5. 12 points] An altimeter set for se](/WebImages/5/im-given-the-answers-just-cant-get-to-the-correct-answers-q5-982801-1761504644-0.webp)
