Solve the equation on the interval 02pi 9 tan2 x 3 0 SOLVE

Solve the equation on the interval [0,2pi).

9 tan^2 x - 3 = 0

SOLVE IN TERMS OF pi

9tan^2x -3 =0

tan^2x = 1/3

tanx = -1/sqrt3 , 1/sqrt3

tanx = -1/sqrt3

x = pi -pi/6 , 2pi -pi/6

x = 5pi/6 , 11pi/6

tanx = 1/sqrt3

x = pi/6 , 7pi/6

Solution : x= pi/6 , 5pi/6 ,7pi/6 , 11pi/6