The following cross is performed involving 5 loci AaBbccDdEE

The following cross is performed involving 5 loci: AaBbccDdEE X AaBbCcddEe What is the probability of an offspring that is AABBCCDDEE? What is the probability of an offspring that is AaBbCcDdEc? What is the probability of an offspring that is aabbccddEE? What is the probability of an offspring that is AaBBccDdEe? What assumption do you have to make for these probabilities to be true?

Solution

AaBbccDdEE x AaBbCcddEe

The probability of any offspring being AABBCCDDEE

The probability of any offspring being AA = 1/ 4, BB = 1 /4, CC = 0, DD=0, EE=1/2 Therefore,AABBCCDDEE = 1/4 × 1/4 × 0 x 0 x 1/2 = 0

(b) The probability of any offspring being AaBbCcDdEe

The probability of any offspring being Aa = 1/ 2, Bb = 1 /2, Cc = 1/2, Dd=1/2, Ee=1/2 Therefore,= 1/2 × 1/2 × 1/2 x 1/2 x 1/2 = 1/32

(C) aabbccddEE

The probability of aa = 1/ 4, bb = 1 /4, cc = 1/2, dd=1/2, Ee=1/2

Therefore, = 1/4 × 1/4 × 1/2 x 1/2 x 1/2 = 1/128

(d) AaBBccDdEe

The probability of Aa = 1/ 2, BB = 1 /4, cc = 1/2, Dd=1/2, Ee=1/2

Therefore, = 1/2 × 1/4 × 1/2 x 1/2 x 1/2 = 1/64

(e) We Assume that all genes are on separate sets of chromosomes