Based on a random sample of hospital reports from Eastern st

Based on a random sample of hospital reports from Eastern states, the following information was obtained (units in percentage of hospitals providing at least some charity care)
57.1, 56.2, 53.0, 66.1, 59.0, 64.7, 70.1, 64.7, 53.5, 78.2

a. Use a calculator with mean and sample standard deviation keys to verify that x = 62.3% and s =8.0%

b. Find a 90% confidence interval for the population average m of the percentage of hospitals providing at least some charity care.

Solution

SAMPLES are

57.1, 56.2, 53.0, 66.1, 59.0, 64.7, 70.1, 64.7, 53.5, 78.2

a. mean and std deviations are

Mean = 62.26

Standard deviation = 8.01

b. Confidence Interval (66.43,58.09)