A B C DSolution2sinx sqrt3 0 sinx sqrt32 sin is ve in IIIr

A=______

B=______

C=______

D=______

2sinx + sqrt3 =0

sinx = -sqrt3/2

sin is -ve in IIIrd and IVrth quadrant

So, x= pi + sin^-1(sqrt3/2) = pi +pi/3 = 4pi/3

x = 2pi -sin^-1(sqrt3/2) = 2pi -pi/3 = 5pi/3

General solutions for the above:

x = 4pi/3 + 2k*pi

x = 5pi/3 +2k*pi

A = 4pi/3

B = 2

C = 5pi/3

D = 2