I dont understand numbers 14 and 15 please help PROBLEM BAS

I don\'t understand numbers 14 and 15, please help..

PROBLEM BAS 12, A plant of genotype is testcrossed wil 18 If the two loci are 10 m apart, what proportion of progeny will be AB/ab 13. The A locus and the Dlocus nked that no are so tightly recombination is ever observed between if Ad 1. Ad is crossed with ab,aD d the F, is intercrossed, what phenotypes will be seen in the Fa and in what proportions? 14. The R and Sloci are 35 m.u. apart. If a plant of genotype is selfed, what progeny phenotypes will be seen and in what proportions 15. The cross EE. FF x efe fif s de, and the F1 is then backcrossed with the recessive parent. The progeny gen. ocypes are inferred from the phenotypes. The progeny genotypes, written as the gametic contributions of the heterozygous parent, are in the following proportions: E. F 2 Explain these results. Progeny Class phenotypes.

Solution

Answers:

14.

R S/r s * R S/r s

Gametes: 1/2 (1 – 0.35) R S

1/2 (1 – 0.35) r s

1/2 (0.35) R s

1/2 (0.35) r S

F1 genotypes will be:

0.1056 R S/R S

0.1138 r s/r S

0.1056 r s/r s

0.1138 r s/R s

0.2113 R S/r s

0.0306 R s/R s

0.1138 R S/r S

0.0306 r S/r S

0.1138 R S/R s

0.0613 R s/r S

F1 phenotypes will be:

0.6058 R S

0.1056 r s

0.1444 R s

0.1444 r S

15. The cross: E/e · F/f * e/e · f/f.

The progeny should be in a 1:1:1:1 ratio if independent assortment takes place, which is not observed. So, linkage exists. E f and e F are recombinants and equals one-third of the progeny.

The two genes are 33.3 map units (m.u.) apart.

RF = 100% * 1/3 = 33.3%