A generator has a coil with 1260 turns that are each 0070 m
A generator has a coil with 1260 turns that are each 0.070 m in diameter. The coil rotates at 3600 rpm in a 0.670 T magnetic field. If a 80.0 resistive load is connected in parallel with the generator, what is the average power used by the load?
Solution
Area of coil
A=pi*D2/4 =pi*0.072/4 =3.85*10-3 m2
Induced Voltage
Vmax=NBAW =1260*0.67*3.85*10-3*(3600 *2pi/60)
Vmax=1225 Volts
Rms Voltage
Vrms =1225/sqrt[2] =866.4 Volts
Average power
Pavg=Vrms2/R =866.42/80
Pavg=9383 W or 9.38 KW
