Kindergarten children have heights that are approximately no
Kindergarten children have heights that are approximately normally distributed about a mean of 39.3 inches and a standard deviation of 2.3 inches. If a random sample of 21 is taken, what is the probability that the sample of kindergarten children has a mean height of less than 38.4 inches? (Give your answer correct to four decimal places.)
Solution
Let X be the random variable that Kindergarten children heights.
X ~ Normal(mean = 39.3 inches, sd = 2.3 inches)
n = sample size = 21
What is the probability that the sample of kindergarten children has a mean height of less than 38.4 inches?
We have to find P(Xbar < 38.4).
And the sampling distribution of Xbar is also Normal with,
mean = 39.3
and s = sd/sqrt(n)
s = 2.3 / sqrt(21) = 0.5019
Now convert Xbar = 38.4 into standard normal distribution.
z = (Xbar - mean) / (sd/sqrt(n)) = (Xbar - mean) / s
z = (38.4 - 39.3) / 0.5019 = -1.7932
Now we have to find P(Z < -1.7932).
This probability we can find by usin EXCEL.
syntax :
=NORMSDIST(z)
where z = -1.7932
P(Z < -1.7932) = 0.0365
The probability that the sample of kindergarten children has a mean height of less than 38.4 inches is 0.0365.

