A raffle is being held at a wheelchair basketball game to ra

A raffle is being held at a wheelchair basketball game to raise money for new team uniforms. Exactly 171 raffle tickets were sold For the raffle, 3 tickets will be drawn and a different prize awarded for each one. Bryant, Arturo, and Garrett each bought 12 tickets. What is the probability that Bryant will win first, then Arturo, and finally Garrett? 818,805 272,935 185,193 1,666,737 Back Next

Solution

The robot chooses 3 different flavors randomly out of 13 flavors. Therefore, the total number of cases i.e. sample space is 13P3 (we are considering permutation as order is important here)

Cory must get a scoop of strawberry as the second scoop. Therefore the event space must contain all such triplet whose middle one is strawberry scoop.

The first scoop can be any flavor except strawberry (i.e. there are 13 – 1 = 12 choices) and the third one can be any flavor except strawberry and the chosen first one (i.e. there are 13 – 2 = 11 choices)

Hence, the event space contains 11 x 12 points.

Hence, the required probability = (11 x 12)/ 13P3    

= (11 x 12)/(11 x 12 x 13) = 1/13 (Answer)

 A raffle is being held at a wheelchair basketball game to raise money for new team uniforms. Exactly 171 raffle tickets were sold For the raffle, 3 tickets wil

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site