A fishing boat traveled 3 hours against a 6kmhr current The
A fishing boat traveled 3 hours against a 6km/hr current. The Return trip took only 2 hours. Find the speed of the boat in still water.
Solution
Distance=(rate)(time)
 It can also be put like this.
 (rate)(time)=(rate)(time)
 We already know the time 3 hours, and 2 hours
 We have to find the speed of the boat.
 .
 speed of the boat in still water = \"x\"
 speed of the boat against current = (x - 6)(current slows the boat\'s speed)
 speed of the boat with the current = (x + 6)(current speeds up the boat\'s speed)
 .
 Now we can solve \"x\"
 We know both the speed(rate) and the time.
 .
 (rate)(time)=(rate)(time)
 .
 (x - 6)(3)= (x + 6)(2)
 .
 3(x - 6)= 2(x + 6)
 .
 We will use the distributive property
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 3x - 18 = 2x + 12
 .
 We will subtract 2x from both sides
 .
 x - 18 = 0 + 12
 .
 Now add 18 to both sides
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 x - 0 = 18 + 12
 .
 x = 30
 .
 The fishing boat went 30 km./hr in still water
 .
 3(30 - 6)= 2(30 + 6)
 3(24)=2(36)
 (72)=(72)
 .
 It went 72 miles each way, 144 miles all together

