In a cross between two individuals heterozygous for three au

In a cross between two individuals heterozygous for three autosomal, independently assorting loci (i.e., A/a; B/b; E/e), what is the probability of getting an offspring whose phenotype differs from both parents?

A. (1/4)^3

B. (1/2)^3

C. 1 - (3/4)^3

D. 1 - (1/4)^3

E. 1 - [(3/4)^3 + (1/4)^3]

Solution

two individuals heterozygous for three autosomal, independently assorting loci (i.e., A/a; B/b; E/e), what is the probability of getting an offspring whose phenotype differs from both parents?

A. (1/4)^3

B. (1/2)^3

C. 1 - (3/4)^3

D. 1 - (1/4)^3

E. 1 - [(3/4)^3 + (1/4)^3] -answer

A/a; B/b; E/e), Gametes for heterozygous (three loci) =2^n=2^3=8

A/a; B/b; E/e), Gametes for heterozygous (three loci) =2^n=2^3=8

Total = 64 offspring

There are 8 distinct phenotypes –trihydrid cross

a trihybrid cross yields a phenotypic ratio of 27:9:9:9:3:3:3:1.

There are 8 distinct phenotypes