In a cross between an individual who is RrPp and one who is
Solution
3. a) As the genotypes are showing 1:1:1:1 ratio, those are not linked genes.
For further conformation adopting chisquare test
Null hypothesis: The observed values are not deviating form the Expected 1:1:1:1 ratio.
Category
RrPp
rrpp
Rrpp
rrPp
Total
Observed values
27
21
25
20
93
Exptected Ratio
1
1
1
1
4
Exprected Values
23.25
23.25
23.25
23.25
Deviation
3.75
-2.25
1.75
-3.25
D^2
14.0625
5.0625
3.0625
10.5625
D^2/E
0.604839
0.217742
0.13172
0.454301
1.408602
X^2
1.408602
Degrees of freedom
4-1
3
Inference: The calculated chi square value is lessthan the table value @ 3 DF and 0.05 probability i.e. 7.815, Hence null hypothesis accepted.
b) As the genes are showing independent assortment, which means both genes are present on same chromosome.
According to chegg guidelines we have to answer one question at a time, so post the other question as sperate question then I can help you.
| Category | RrPp | rrpp | Rrpp | rrPp | Total |
| Observed values | 27 | 21 | 25 | 20 | 93 |
| Exptected Ratio | 1 | 1 | 1 | 1 | 4 |
| Exprected Values | 23.25 | 23.25 | 23.25 | 23.25 | |
| Deviation | 3.75 | -2.25 | 1.75 | -3.25 | |
| D^2 | 14.0625 | 5.0625 | 3.0625 | 10.5625 | |
| D^2/E | 0.604839 | 0.217742 | 0.13172 | 0.454301 | 1.408602 |
| X^2 | 1.408602 | ||||
| Degrees of freedom | 4-1 | 3 |

