Homework SourseAn analysis of variance experiment produced a portion of the
An analysis of variance experiment produced a portion of the accompanying ANOVA table.
| An analysis of variance experiment produced a portion of the accompanying ANOVA table. |
Solution
(a)
Following is the completed table:
(b)
H0: A = B = C = D; HA: Not all population means are equal.
(c)
Since p-value is greater than 0.01 so we fail to reject the null hypothesis. So option \"Do not reject H0; the population means are not unequal.\" is correct.
| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | p-value | F crit |
| Between Groups | 17.27 | 3 | (17.27/3)=5.7567 | (5.7567/1.4401)=3.9974 | 0.0111 | 4.088 |
| Within Groups | 96.49 | 67 | (96.49/67)=1.4401 | |||
| Total | 113.76 | 70 |
