Write the equation of a line that is perpendicular to the gi

Write the equation of a line that is perpendicular to the given line and that passes through the given point

y-4= 5/2 (x +3); (-7,8)

we are given y-4=5/2(x+3)

we see that we have slope = 5/2

since w e need to find an equation perpendicular of it

so slope of normal will be m=-2/5 and passes through ( -7,8)

y-y1=m(x-x1)

y-8=-2/5(x+7) that would be our new equation in slope point form

y-8=-2/5x-14/5

y=-2/5x-14/5+8

y=-2/5x+26/5 answer