It has been found that burning 1 liter or 074 kg of gasoline

It has been found that burning 1 liter, or 0.74 kg, of gasoline reduces its rest mass by

Solution

E = m c²

c = 3 * 10⁸ m/s

(3.8 * 10^-10) / (0.74) = 5.14 * 10^-10

For fission solve for m

8.0 * 10¹³ J = m * c²

m = 8.0 * 10¹³ / (3 * 10⁸)² = 8.88 * 10^-4 kg

ratio of the fractional decrease in mass of the nuclear fuel to the fractional decrease in mass of gasoline

8.88 * 10^-4/ 5.14 * 10^-10 = 1.73 * 10⁶