At condition 1 a piston cylinder device contains a liquid a

At condition 1 a piston cylinder device contains a liquid a raptor mixture with quality x_1 = 0.85, at a saturations temperatures of T_1 = 105.0 degree c. Volume V_e = 0.0010 m^3 and piston diamatur d_p = 0.15 m. The system is heated to condition Z the water to V_z 0.0018 m^3. At this point the piston the piston is about to angular a linear sparing Determine The mass m of the water The parcentage F_e The state of the water The matrix done in from condition I to condition W Halting continues and the spring of stiffness compassed until the P_B 800.0 R Determine Final system temperature T_3 The work done removing from condition e to condition 3 2 W Total work done At the end of your solution list your answers True in a neat clear table.

Solution

From steam mixture properties,

At T1 = 105 deg C and x1 = 0.85, we get v1 = 1.21 m^3/kg, P1 = 121 kPa, u1 = 2200 kJ/kg, h1 = 2350 kJ/kg

a)

m = V1/v1 = 0.001 / 1.21 = 8.264*10^-4 kg

b)

Since heating is happening at constant pressure, we get

P2 = P1 = 121 kPa

c)

v2 = V2 / m = 0.0018 / 8.264*10^-4 = 2.178 m^3/kg

From steam properties at P2 = 121 kPa, we get for sat. vapor v = 1.42 m^3/kg.

Since v2 = 2.178 m^3/kg > 1.42 m^3/kg, we get the quality of steam at 2, x2 = superheated

d)

Work done = P*(V2 - V1)

= 121*(0.0018 - 0.001)

= 0.0968 kJ