A plane flying a straight course observes a mountain at a be
     A plane flying a straight course observes a mountain at a bearing of 31.4 degree to the right of its course. At that time the plane is 6 km from the mountain. A short time later, the bearing to the mountain becomes 41.4 degree. How far is the plane from the mountain when the second bearing is taken (to the nearest tenth of a km)?  7.6 km  3.2 km  4.7 km  8.6 km 
  
  Solution
6 x sin31.4 = d x sin(41.4)
d = 4.727 km = 4.7 km

