Marcus and Tony work for the same company Marcus lays a slab

Marcus and Tony work for the same company. Marcus lays a slab of concrete in 3 hours. Tony lays the same size slab in 7 hours. If both work on the job and the cost of labor is$ 60.00 per hour, decide what the labor estimate should be.

Solution

Solution: - Marcus lays slab in 3hrs. So in one hr he works 1/3 job

In the same manner Tony works 1/7 job

in 1 hr total job = (1/3 +1/7) = 10/21

Hence to finish the job total hrs are required = 21/10 = 2.1 hr

Total cost for the work = 2.1 X 60 = $126

3 Marcus = 7 Tony

1 Marcus = 7/3 Tony

M + T = 126

7/3 T +T = 126

10 T/3 =126

T = $ 37.8

M = 126 - 37.8 = $88.2