You will mix 3 liters of a 05 M Sodium Chloride with 500 ml

You will mix 3 liters of a 0.5 M Sodium Chloride with 500 ml of a solution of 1 M Sodium Chloride. What is the concentration of mixed solution.

Answer :

[NaCl] dilution 1: = (0.5M x 3000ml)/3500 ml = 0.428M = 0.43 M

[NaCl] dilution 2 = (1M x 500ml)/3500 ml = 0.1428 M = 0.14 M

[NaCl] Total = 0.43 + 0.14 M

= 0.57 M

or in the other way

using M1V1+M2V2 = M3V3

we can again find the answer

(0.5)(3000) + (1) (500) = (M3) (3500)

M3 = (1500+500)/ 3500

= 2000/3500

= 0.57 M

Therefore the answer is 0.57M