Double stranded genomic DNA from the bacterium Mycobacterium

Double stranded genomic DNA from the bacterium Mycobacterium tuberculosis has 33% G. How much A does it have? How about T?

Solution

The amount of A will be 33%.

The amount of T will be 22%.

According to Chargaff\'s rule A+G/T+C=1 that means total amount of purines equal to total amount of pyrimidine.

Here amount of guanine is 33% so adenine will be also 33% total (33+33)%=66% is purine then amount of pyrimidine is (100-66)%=44% so here thymine+cytosine=44% hence amount of thymine will be 44%/2=22%.