A ranger in tower A spots a fire at a direction of 318 A ran

A ranger in tower A spots a fire at a direction of 318°. A ranger in tower B, located 40 mi at a direction of 47 from tower A, spots the fire at a direction of 283 How far from tower A is the fire? How far from tower B? The fire is in a direction of 318 from tower A /47 283 Tower B is 40 miles away from A in a direction of 47 mi 31s From tower B, the fire\'s direction is 283 In triangle ABC, A= 89 c 40 mi C 318 -283 35° B 56 Since two angles and a side are known, use the law of sines. First find side a

Solution

Ange A = sum of two angles

angle1 = 360 -318 = 42 deg

angle2 = 47 deg

Ange A = sum of two angles = 42 +47 = 89 degrees

I hope it asweres your question

 A ranger in tower A spots a fire at a direction of 318°. A ranger in tower B, located 40 mi at a direction of 47 from tower A, spots the fire at a direction of

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