A telephone subscriber line has a frequency range of 300 Hz

A telephone subscriber line has a frequency range of 300 Hz to 3300 Hz and a minimum SNR_dB of 48 Find the minimum sampling rate for a signal in this line What is the minimum number of bits per sample What is the bit rate

Solution

a)minimim sampling rate-2*max_frequency=2*3300=>6600 hz

b)minimum number of bites per sample=

6.6nb+1.76=48

6nb=48-1.76=46.24

6nb=46.24

nb=46.24/6=7.70

3)Bit rate=6600*8=52800 bps