It is reported that 5 of students calculators fail during a

It is reported that 5% of students calculators fail during a test. 100 Students are taking a test, what is the probability that at least one will have their calculator fail? Using binomial normal approximation without continuity correction, (give your answer to three decimal places).

Solution

Note that

P(at least one fail) = 1 - P(none fail)

= 1 - (1-0.05)^100

= 0.994079471 [answer]