A recent survey asKed how many hours within the average day

A recent survey asKed \"how many hours, within the average day do you watch television?

Sample size: 1324, Mean : 2.9800, SD : 2.6600, S error:0.0731 95% Confidence Limit

Qa Interpret the 95% confidence interval

Qb What do the sample mean and sd suggest about the likely shape of the population distribution ?

Solution

Confidence Interval Estimate for the Mean

Data

Standard Deviation

2.66

Sample Mean

2.98

Sample Size

1324

Confidence Level

95%

Intermediate Calculations

Standard Error of the Mean=se=sd/sqrt(n)=2.66/sqrt(1324)=

0.0731

Z Value

1.9600

Margin of error=me=se*z=

0.1433

Confidence Interval

Interval Lower Limit =mean-me=

2.84

Interval Upper Limit=mean+me=

3.12

Qa Interpret the 95% confidence interval

We are 95% confident that all the people watching TV falls in the interval (2.84, 3.12)

Qb What do the sample mean and sd suggest about the likely shape of the population distribution ?

Since Sd is as large as mean and the variable is time, the shape of the distribution may be positively skewed

Confidence Interval Estimate for the Mean

Data

Standard Deviation

2.66

Sample Mean

2.98

Sample Size

1324

Confidence Level

95%

Intermediate Calculations

Standard Error of the Mean=se=sd/sqrt(n)=2.66/sqrt(1324)=

0.0731

Z Value

1.9600

Margin of error=me=se*z=

0.1433

Confidence Interval

Interval Lower Limit =mean-me=

2.84

Interval Upper Limit=mean+me=

3.12

A recent survey asKed \
A recent survey asKed \

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