2x3y5 5x4y1 solve using substitutionSolution2x3y5 equation1

2x-3y+=5 5x+4y=1 solve using substitution

Solution

2x-3y+=5 -->equation1

5x+4y=1 --->equaion2

so 5x = 1-4y substitue in equation1

2(1-4y)/5 -3y =5

2/5 -8/5y -3y=5-

-23y/5 = 5 -2/5

-23y/5 = 23/5

y = -23/23 = -1

now plug y value in equation1

2x -3(-1) = 5

2x +3 =5

2x= 2

x=1

so (x=1, y=-1)