Final Examination Codon Table Final Examination 42 9 points
Solution
Answers:
(42) (A)
Since red hair is recessive (rr), we get
r2 = 4/100
so, r = 0.2
According to Hardy Weinberg equilibrium, R2 + 2Rr + r2 = 1...........................(1)
Also, R + r = 1
Therefore R = 1 - 0.2 = 0.8
Thus, frequencies of the red and non red alleles are 0.2 (r) and 0.8 (R).
(B) Frequency of heterozygote = 2Rr
= 2 * 0.8 * 0.2
= 0.32
(C) Proportion of matings that can have red hair (rr) can be calculated as under:
(i) Rr * Rr = 0.32 * 0.32 = 0.1024
(ii) Rr * rr = 0.32 * 0.04 * 2 = 0.0256
(iii) rr * rr = 0.04 * 0.04 = 0.0016
So, proportion with red hair = 0.1296
Therefore, thw proportion of matings that cannot give red hair = 1 - 0.1296 = 0.8704
(43) The 3 central principles of Darwin\'s theory of evolution are stated below:
(a) A species is a group of organisms which can interbreed and produce fertile offsprings.
(b) Living organisms have decended from previous organisms (species) with modifications.
(c) Natural selection explains for adaptation and speciation. It states that phenotypic variation exists within populations which are heritable. The individuals with the heritable trait better suited to the environment will survive and others will become extinct (Survival of the fittest).
