Heres my problem INTEGRAL SIGN sin2xcosx dx The answer is ap
Here\'s my problem:
INTEGRAL SIGN: sin^2(x)cos(x) dx
The answer is apparently
sin^3(x)/3 + C
NEED ANSWER, ENGLISH LANGUAGE NOT MATH JUMBO MUMBO
INTEGRAL SIGN: sin^2(x)cos(x) dx
The answer is apparently
sin^3(x)/3 + C
NEED ANSWER, ENGLISH LANGUAGE NOT MATH JUMBO MUMBO
Solution
let say that X=sin(x) so dx would be d(sinx) = cos(x) right?
and x2 would be sin2(x)
now if we need X2dX... that would be X3/3 + C right? and now replace that X by sin(x) and we get sin^3(x)/3 + C
