Use the Laplace transform to solve the following initial val

Use the Laplace transform to solve the following initial value problem f(t)= {t 0 lessthanorequalto t

Solution

Laplace transform of f(t) = 1 is given by,

L{f(t)} = 1/s           when 1 t <

Laplace transform of f(t) = t is given by,

L{f(t)} = (1!)/(s¹⁺¹) = 1/s²    when 0 t < 1

(Answer)