find value sigma n1 infinity 2n 3nSolutionsigma n1 infinity

find value
sigma (n=1, infinity) 2^n / 3^n

sigma (n=1, infinity) 2^n / 3^n

(2/3)^n

= (2/3) / (1-2/3)

= 2/3 / 1/3

= 2

find value sigma (n=1, infinity) 2^n / 3^nSolutionsigma (n=1, infinity) 2^n / 3^n (2/3)^n = (2/3) / (1-2/3) = 2/3 / 1/3 = 2

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