Find area of a triangle having two sides 8 and 6 and in incl
     Find area of a triangle having two sides 8 and 6, and in included angle of 30^degree.  Find the area of a triangle have three sides 10, 18, and 16. 
  
  Solution
3. Area of triangle having sides a and b and the including angle x is given by
A=(1/2)(ab) Sinx
Here a= 8 , b=6 , x=30
A=1/2(8*6) sin 30 = (1/2)(48)(1/2)=12
4. Area of triangle having sides a,b and c is given by
A=sqrt(s(s-a)(s-b)(s-c))
where s=(a+b+c)/2
Here a=10 , b=18 , c=16
s=(10+18+16)/2=22
A=sqrt(22(22-10)(22-18)(22-16))=sqrt(22*12*4*6)= 24 sqrt11=79.6

